Created
September 6, 2019 07:51
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| def my_round(x, prec=2, base=0.05): return (base * (np.array(x) / base).round()).round(prec) |
x // base * base
math.ceil((math.floor(math.log(256,2)+1))/8)*8
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For rounding to non-integer values, such as 0.05:
def myround(x, prec=2, base=.05):
return round(base * round(float(x)/base),prec)
I found