Created
June 4, 2011 17:43
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Long Math
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
#define NMAX 1002 | |
void invert(int*); // Инвертирует число | |
void sum(int*, int*); // Суммирует два числа | |
int max(int, int); // Возвращает максимальное число | |
int* divide (int*, int); | |
int main() | |
{ | |
freopen("input.txt", "r", stdin); | |
freopen("output.txt", "w", stdout); | |
int* nums[NMAX]; | |
int* general; | |
int* average; | |
int* result; | |
int i = 0, j = 1, m = 0; | |
int x; | |
char c; | |
for (m = 0; m < NMAX; m++) nums[m] = (int*)malloc(NMAX*sizeof(int)); | |
general = (int*)malloc(NMAX*sizeof(int)); | |
average = (int*)malloc(NMAX*sizeof(int)); | |
result = (int*)malloc(NMAX*sizeof(int)); | |
while (scanf("%c", &c) > 0) { | |
if (c >= '0' && c <= '9') { | |
nums[i][j] = c - '0'; | |
j++; | |
} else | |
if (j > 1) { | |
nums[i][0] = j-1; | |
i++; | |
j = 1; | |
} | |
} | |
if (j > 1) { | |
nums[i][0] = j-1; | |
i++; | |
} | |
//printf("%d\n", i); | |
for (x = 0; x < NMAX+1; x++) general[x] = 0; | |
for (x = 0; x < i; x++) { | |
invert(nums[x]); | |
sum(general, nums[x]); | |
} | |
//for (j = 1; j <= general[0]; j++) printf("%d", general[j]); | |
//printf("\n"); | |
result = divide(general, i); | |
invert(result); | |
for (i = 1; i <= result[0]; i++) printf("%d", result[i]); | |
return 0; | |
} | |
void invert(int* mass) { | |
int x; | |
int i; | |
for (i = 1; i <= mass[0]/2; i++) { | |
x = mass[i]; | |
mass[i] = mass[mass[0]-(i-1)]; | |
mass[mass[0]-(i-1)] = x; | |
} | |
} | |
void sum(int* to, int* from) { | |
int i, j = 0; | |
to[0] = max(to[0], from[0]); | |
for (i = 1; i <= max(to[0], from[0]); i++) { | |
to[i] = to[i] + from[i]; | |
if (to[i] >= 10) { | |
to[i] = to[i]-10; | |
to[i+1] = to[i+1] + 1; | |
if (i + 1 > to[0]) j++; | |
} | |
} | |
to[0] += j; | |
} | |
int max(int x1, int x2) { | |
return x1 >= x2 ? x1 : x2; | |
} | |
int* divide(int* a, int b) { | |
int r = 0; | |
int i; | |
int* result; | |
result = (int*)malloc(a[0]*sizeof(int)); | |
for(i = a[0]; i >= 1; i--) { | |
r = r * 10 + a[i]; | |
result[i] = r / b; | |
r %= b; | |
} | |
result[0] = a[0]; | |
while (result[0] > 1 && result[result[0]] == 0) --result[0]; | |
return result; | |
} |
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