Created
September 22, 2011 15:54
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Permutations in Go
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// By: Robert Wallis - [email protected] | |
// Returns a channel of all the possible permutations of a string containing | |
// r length in characters. | |
// adopted from http://docs.python.org/library/itertools.html | |
func StringPermutationsSub(s string, r int) chan string { | |
out := make(chan string) | |
go func() { | |
defer close(out) | |
pool := []int(s) // get unicode | |
n := len(pool) | |
if r > n { | |
return | |
} | |
indices := make([]int, n) | |
for i := 0; i < n; i++ { | |
indices[i] = i | |
} | |
cycles := []int{} | |
for i := n; i > n-r; i-- { | |
cycles = append(cycles, i) | |
} | |
endOfCycles := make([]int, len(cycles)) | |
copy(endOfCycles, cycles) | |
// send the first iteration | |
sout := make([]int, r) | |
for i, v := range indices[:r] { | |
sout[i] = pool[v] | |
} | |
out <- string(sout) | |
for n > 0 { | |
reversedRangeR := []int{} | |
for i := r - 1; i >= 0; i-- { | |
reversedRangeR = append(reversedRangeR, i) | |
} | |
for _, i := range reversedRangeR { | |
cycles[i] = cycles[i] - 1 | |
if cycles[i] == 0 { | |
// time for a new cycle | |
newindices := make([]int, i) | |
for k := 0; k < i; k++ { | |
newindices[k] = indices[k] | |
} | |
for k := i + 1; k < len(indices); k++ { | |
newindices = append(newindices, indices[k]) | |
} | |
newindices = append(newindices, indices[i]) | |
indices = newindices | |
cycles[i] = n - i | |
} else { | |
j := cycles[i] | |
indices[i], indices[len(indices)-j] = indices[len(indices)-j], indices[i] | |
// send iteration | |
sout := make([]int, r) | |
for k, v := range indices[:r] { | |
sout[k] = pool[v] | |
} | |
out <- string(sout) | |
break | |
} | |
} | |
// have we come all the way around to the first permutation? | |
same := true | |
for i, v := range cycles { | |
if endOfCycles[i] != v { | |
same = false | |
break | |
} | |
} | |
if same { | |
// yes this is the same as the first | |
return | |
} | |
} | |
// end | |
return | |
}() | |
return out | |
} |
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