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@rochacbruno
Created June 6, 2012 17:43
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Calculate distance between latitude longitude pairs with Python
#!/usr/bin/env python
# Haversine formula example in Python
# Author: Wayne Dyck
import math
def distance(origin, destination):
lat1, lon1 = origin
lat2, lon2 = destination
radius = 6371 # km
dlat = math.radians(lat2-lat1)
dlon = math.radians(lon2-lon1)
a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1)) \
* math.cos(math.radians(lat2)) * math.sin(dlon/2) * math.sin(dlon/2)
c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
d = radius * c
return d
@joaovs12
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joaovs12 commented Sep 4, 2019

Hello, I have a list with 700 cities and I want to find the city where the sum of distances will be minimun
I defined a function that will give me that sum, but what I should do to find the lat,long where the sum of distances will be minimum? tks

@zuzhaoye
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Thank you! @MalyutinS

@manikyalarao16
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Hello i have two co-ordinates values sources and destination ,my source co-ordinates values are changing when i move robot , for that i have to calculate distance for each positional values pls help me how to write python code for that

@vivek1240
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vivek1240 commented Jun 11, 2020

Hello i have two co-ordinates values sources and destination ,my source co-ordinates values are changing when i move robot , for that i have to calculate the distance for each positional values pls help me how to write python code for that

#I am adding the code to calculate the distance between two coordinates, you can call this function inside a for loop to get the distance between source and destination as soon as your bot makes a displacement.

def distance(source , destination): 
    lat1, lon1 = source [0],source [1]
    lat2, lon2 = destination[0],destination[1]
    radius = 6371 # km
    dlat = math.radians(lat2-lat1)
    dlon = math.radians(lon2-lon1)
    a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1)) \
        * math.cos(math.radians(lat2)) * math.sin(dlon/2) * math.sin(dlon/2)
    c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
    d = radius * c
    d = d*1000  #Converting distance to Metre as bot will make small displacements
    return d

#CALLING THE FUNCTION

source = [lat1, lon1] #Coordinates for the initial position of the robot
distance_measured = 0 #initially total distance covered by bot is 0.
Loop:
   new_latitude = GPS.latitude #  get current latitude of bot
   new_longitude = GPS.longitude # get current longitude bot
   destination = [new_latitude , new_longitude ]
   if (distance(source, destination) != 0):
         distance_measured = distance_measured + distance(source, destination)
         last_latitude = new_latitude  
	 last_longitude = new_longitude
         source =[last_latitude,last_longitude] 

Hope this helps!!

@AsadTanvir
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AsadTanvir commented Jul 28, 2020

Hello, thank you very much for this masterpiece. But my concern is how to do so when you have an excel file, I have bunch of cities and finding the distance from those cities to one reference point (which is also a city). Thanks

Hello @Zagroz, did you able to find the distances from an excel file using this code? I am also stuck in similar kind of situation. Thank you!

@vivek1240
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Hello, thank you very much for this masterpiece. But my concern is how to do so when you have an excel file, I have a bunch of cities and finding the distance from those cities to one reference point (which is also a city). Thanks

Hello @Zagroz, did you able to find the distances from an excel file using this code? I am also stuck in a similar kind of situation. Thank you!

Hello, I have implemented something similar to what you are trying to do. You can visit my repo which involves what you desire. The link is here:

https://github.com/vivek1240/k-means-clustering-via-haversine-distance-/blob/master/clustering_stores_via_haversine_distance_kmeans.ipynb

Please inform if this solves your problem.
All the Best!!

@biyak
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biyak commented Nov 11, 2020

Thanks for the eloquent and easily understandable code!

@sreedhar007
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Thanks for this, can anyone explain what are 'a' and 'c' assignments , can we have better names for these variables ?

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