Skip to content

Instantly share code, notes, and snippets.

@rofl0r
Created August 6, 2013 21:15
Show Gist options
  • Select an option

  • Save rofl0r/6168719 to your computer and use it in GitHub Desktop.

Select an option

Save rofl0r/6168719 to your computer and use it in GitHub Desktop.
minimal init daemon by rich felker, author of musl libc
#define _XOPEN_SOURCE 700
#include <signal.h>
#include <unistd.h>
int main()
{
sigset_t set;
int status;
if (getpid() != 1) return 1;
sigfillset(&set);
sigprocmask(SIG_BLOCK, &set, 0);
if (fork()) for (;;) wait(&status);
sigprocmask(SIG_UNBLOCK, &set, 0);
setsid();
setpgid(0, 0);
return execve("/etc/rc", (char *[]){ "rc", 0 }, (char *[]){ 0 });
}

ghost commented Apr 14, 2023

Copy link
Copy Markdown

Just go outside instead of turning on your computer. It uses 0B of disk space

ghost commented May 17, 2023

Copy link
Copy Markdown

I'm 100% sure this is way too slow. We need to write this in assembly. So that it'll fit in 1 sector of a drive.

ghost commented May 17, 2023

Copy link
Copy Markdown

I like shell scripts that don't need to be recompiled... A mount -a && /etc/rc works just fine

@yurayko

yurayko commented Nov 25, 2023

Copy link
Copy Markdown

Is it not possible to straight up execute the /etc/rc script? Just by adding init=/etc/rc to the kernel command line?

You need a always running daemon, who will be reap a zombie. It is single work for init.
If you redirect this job to /etc/rc, you got a systemd again.
You cannot start an another daemon from /etc/rc for this. Zombie go to process with PID 1. /etc/rc have a PID 1 in your case.

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment