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Multithreaded Merge Sort
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import _thread | |
from threading import Thread | |
class MergeSorter: | |
def merge(self, left, right, myArray): | |
i = 0 | |
j = 0 | |
k = 0 | |
while i < len(left) and j < len(right): | |
if (left[i] < right[i]): | |
myArray[k] = left[i] | |
i += 1 | |
else: | |
myArray[k] = right[j] | |
j += 1 | |
k += 1 | |
# remaining | |
while i < len(left): | |
myArray[k] = left[i] | |
i += 1 | |
k += 1 | |
while j < len(right): | |
myArray[k] = right[j] | |
j += 1 | |
k += 1 | |
def mergeSort(self, myArray): | |
left = [] | |
right = [] | |
n = len(myArray) | |
if n < 2: | |
return | |
mid = n // 2 | |
for i in range(mid): | |
left.append(myArray[i]) | |
for i in range(mid, n): | |
right.append(myArray[i]) | |
print(left, right) | |
#thread1 = _thread.start_new_thread(self.mergeSort, (left,)) #mergeSort(left) | |
#thread2 = _thread.start_new_thread(self.mergeSort, (right,)) #mergeSort(right) | |
thread1 = Thread(target=self.mergeSort, args=(left,)) | |
thread2 = Thread(target=self.mergeSort, args=(right,)) | |
thread1.start() | |
thread1.join() | |
thread2.start() | |
thread2.join() | |
self.merge(left, right, myArray) | |
foo = MergeSorter() | |
myArray = [4, 3, 2, 1] | |
foo.mergeSort(myArray) | |
while True: | |
print(myArray) |
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