how to grep docker log

dockergrep.sh

docker logs nginx 2>&1 | grep "127." 

# ref: http://stackoverflow.com/questions/34724980/finding-a-string-in-docker-logs-of-container

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Thank you

Whoa! Thanks! So docker logs to stdder, and then grep just passes everything in stderr through?

More like stderr is redirected to stdout. grep does what it always does afterwards.

Perfect! Thanks :) 👍

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thank you!

Thanks!!!

牛逼！

thanks

Thanks

love your work

based man

More flexible, take the container ID as the first argument, and pass remaining arguments to grep

#!/usr/bin/env bash
#
# Docker outputs logs to stderr not stdout, redirect output for the specified container and
# pass remaining arguments to grep
# 
# Usage:
#   dockergrep.bash [container ID] -i error
#   dockergrep.bash [container name] 127.
#   dockergrep.bash [container name] -C 3 Successfully
#   
docker logs "$1" 2>&1 | grep "${@:2}" 

# ref: http://stackoverflow.com/questions/34724980/finding-a-string-in-docker-logs-of-container

thks

you are powerful

excellent！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！ You are the one who knows "2>&1" well.

if you get "grep: (standard input): binary file matches" error, when doing e.g. --since=48h, try this:

docker logs nginx 2>&1 | grep -a "127."

Thanks!

Thanks!

Thanks

thanks

Gracias!

wow, the same level as Alan Turing. Thanks

thanks

Whoa! Thanks! So docker logs to stdder, and then grep just passes everything in stderr through?

More like stderr is redirected to stdout. grep does what it always does afterwards.

ah yeah, thanks