inFullMobile Language Wars: Round 1 - Old JavaScript Solution 2 by @rsp - See: https://gist.github.com/rsp/d8bdbafa09f24f99eebc8ed60fe205c8

ifm-lw-r1-ojs-solution-2.js

function e(a) {
  return function (b) {
    return function (c) {
      return c ? e(b(a))(b)(c - 1) : a;
    };
  };
}

function f(a) {
  return function (b) {
    return function (c) {
      return e(c)(b)(a(function (a) { return a + 1; })(0) - 1);
    };
  };
}