find.js

function *find(total, count, [val, ...remaining]) {
  if (!count && Math.abs(total) < 0.001) yield [];
  if (!count || total < 0 || !val) return;

  for (let i = 0; i <= count; i++, total -= val)
    for (let counts of find(total, count - i, remaining))
      yield [i, ...counts];
}

for (let solution of find(100, 100, [3.44, 2.87, 1.99, 0.59]))
  console.log(solution);