Flask-Admin simple helpers: require login mixing, serving protected static pages. Snippet is written for Python 3.x

flask_admin_helpers.py

# No Rights Reserved
# http://creativecommons.org/publicdomain/zero/1.0/

"""
Flask-Admin simple helpers
==========================

Just copy and paste to some of your helpers or base classes module, import and use.
You'll also need to install Flask-Login for using authentication.

Example for `AuthRequiredMixin` is `StaticPagesView` class itself.

Example for `StaticPagesView`::

    # ... Flask admin setup ...
    docs_home_dir = '/home/user/project/docs'
    admin.add_view(StaticPagesView(name='Docs', url='docs', home=docs_home_dir))

Cheers!

"""
from werkzeug.exceptions import NotFound
from flask import send_from_directory
from flask.ext import admin
from flask.ext import login


class AuthRequiredMixin:
    """ Mixin for Flask-Admin views to require login.
    """
    def is_accessible(self):
        return login.current_user.is_authenticated()


class StaticPagesView(AuthRequiredMixin, admin.BaseView):
    """ Flask-Admin view to serve protected static pages.
    """
    def __init__(self, *args, **kwargs):
        self.home = kwargs.pop('home').rstrip('/')
        super().__init__(*args, **kwargs)

    @admin.expose('/')
    def index(self):
        return self.pages('')

    @admin.expose('/<path:page>')
    def pages(self, page):
        if not page or page.endswith('/'):
            index_file = page and ('%s/index.html' % page.strip('/')) or 'index.html'
            return send_from_directory(self.home, index_file)
        else:
            return send_from_directory(self.home, page)

For both compatible 2.x and 3.x code just use future module.

from future.builtins import super
# and use super().__init__() in 2.x!

And class AuthRequiredMixin(object) declaration is valid in Python 3.x as well.