Created
January 16, 2013 14:27
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Converting decimal numbers into floating point binary (Excess 64 format).
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import math | |
# This solution assumes valid input in terms of type and range. | |
# Main returns the sign, exponent and mantissa in "Excess 64" format. | |
def main(): | |
value = float(input("Enter a number. ")) | |
sign = "0" | |
if value < 0: | |
sign = "1" | |
value = abs(value) | |
exponent = math.floor(math.log(value, 2)) | |
mantissa = (value / (2 ** exponent)) - 1 | |
mantissa = getBinary(mantissa, 0.5, 8) | |
exponent = getBinary(exponent + 64, 2 ** 6, 7) | |
return sign + exponent + mantissa | |
def getBinary(value, bitValue, bits): | |
binary = "" | |
for i in range(bits): | |
if value >= bitValue: | |
binary += "1" | |
value -= bitValue | |
else : | |
binary += "0" | |
bitValue /= 2 | |
return binary |
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