Created
June 25, 2016 11:47
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#include<stdio.h> | |
long int is_prime(long int n) | |
{ | |
int bool = 0;//nが素数かどうかの判定 | |
if(n > 1) | |
{ | |
long int count = 0;//2からnまで走査し、割り切れたものをカウント | |
for(long int k=1;k<(n+1);k++) | |
{ | |
if(n%k == 0) | |
{ | |
count++; | |
} | |
} | |
bool = (count == 2) ? 1 : 0; | |
} | |
else | |
{ | |
bool = 1;//1の場合は割り切れる整数の個数が1個となるので、例外処理 | |
} | |
return bool; | |
} | |
/*1からnまでの整数の個数について調べる*/ | |
long int number_of_prime(long int n) | |
{ | |
int count = 0; | |
for(long int k=1;k<(n+1);k++) | |
{ | |
count += is_prime(k); | |
} | |
return count; | |
} | |
int main() | |
{ | |
/* | |
printf("number_of_prime[1,10]=%ld\n",number_of_prime(10)); | |
printf("number_of_prime[1,100]=%ld\n",number_of_prime(100)); | |
printf("number_of_prime[1,1000]=%ld\n",number_of_prime(1000)); | |
printf("number_of_prime[1,10000]=%ld\n",number_of_prime(10000)); | |
*/ | |
printf("number_of_prime[1,100000]=%ld\n",number_of_prime(20000)); | |
//printf("number_of_prime[1,1000000]=%ld\n",number_of_prime(1000000)); | |
} |
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