Created
November 4, 2024 01:38
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Find all numbers disappeared in an array
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/** | |
* @param {number[]} nums | |
* @return {number[]} | |
*/ | |
var findDisappearedNumbers = function(nums) { | |
let ans = []; | |
for(let i=0; i<nums.length; i++) { | |
if(nums[Math.abs(nums[i]) - 1] < 0) continue; | |
nums[Math.abs(nums[i]) - 1] = -nums[Math.abs(nums[i]) - 1]; | |
} | |
for(let i=0; i<nums.length; i++) { | |
if(nums[i] > 0) ans.push(i+1); | |
} | |
return ans; | |
}; | |
// Iterate through the array and negate the element at index equal to the current element - 1 | |
// ex: [4, 2, 1 ,3 , 5, 5] element at 0 = 4 ==> mark element at nums[4 - 1] as -nums[4 - 1] | |
// at the end, iterate through the array again and add the (index + 1) of elements which are greater than 0 to the ans array | |
// Time: O(n) | |
// Space: O(1) |
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