pythonのデジタルフィルタ

filter.py

import numpy as np
from scipy import signal

def myFilter(inData, filter):
    dt = 4.1666666667
    fn = 1 / (2 * dt)
    fp = 2
    fs = 3
    gpass = 1
    gstop = 40
    Wp = fp / fn
    Ws = fs / fn
    window_size = 10
    
    if filter == "None":
        return inData
    elif filter == "Buttord":
        N, Wn = signal.buttord(Wp, Ws, gpass, gstop)
        b1, a1 = signal.butter(N, Wn, "low")
        return signal.filtfilt(b1, a1, inData)
    elif filter == "Cheb1ord":
        N, Wn = signal.cheb1ord(Wp, Ws, gpass, gstop)
        b2, a2 = signal.cheby1(N, gpass, Wn, "low")
        return signal.filtfilt(b2, a2, inData)
    elif filter == "Cheb2ord":
        N, Wn = signal.cheb2ord(Wp, Ws, gpass, gstop)
        b3, a3 = signal.cheby2(N, gstop, Wn, "low")
        return signal.filtfilt(b3, a3, inData)
    elif filter == "Ellipord":
        N, Wn = signal.ellipord(Wp, Ws, gpass, gstop)
        b4, a4 = signal.ellip(N, gpass, gstop, Wn, "low")
        return signal.filtfilt(b4, a4, inData)
    elif filter == "Bessel":
        N = 4
        b5, a5 = signal.bessel(N, Ws, "low")
        return signal.filtfilt(b5, a5, inData)
    elif filter == "FIR":
        a6 = 1
        numtaps = len(inData)
        b6 = signal.firwin(numtaps, Wp, window="hann")
        return signal.lfilter(b6, a6, inData)
        delay = (numtaps - 1) / 2 * dt
    elif filter == "Median":
        return signal.medfilt(inData, window_size)