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Codility Lesson 8
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class Solution { | |
public int solution(int[] A) { | |
int[] a = new int[A.length]; | |
int peak = -1; | |
for (int i=0; i<A.length; i++) { | |
if (i > 0 && i < A.length-1) | |
if (A[i] > A[i-1] && A[i] > A[i+1]) | |
peak = i; | |
a[i] = peak; | |
} | |
if (peak < 0) | |
return 0; | |
for (int i=2; i<A.length; i++) { | |
if (A.length % i == 0) { | |
int n = 0; | |
for (int j=0; (j+i)<=A.length; j+=i) { | |
if (a[j+i-1] >= j && a[j+i-1] < j+i) | |
n++; | |
else | |
break; | |
} | |
if (n == A.length/i) | |
return n; | |
} | |
} | |
return 1; | |
} | |
} | |
// another solution | |
// uses the same logic, though iterates through the half | |
// of the values of the group size | |
class Solution { | |
public int solution(int[] A) { | |
int[] a = new int[A.length]; | |
int peak = -1; | |
for (int i=0; i<A.length; i++) { | |
if (i > 0 && i < A.length-1) | |
if (A[i] > A[i-1] && A[i] > A[i+1]) | |
peak = i; | |
a[i] = peak; | |
} | |
if (peak < 0) | |
return 0; | |
int num = 1; | |
int i = 2; | |
while (i*i <= A.length) { | |
if (A.length % i == 0) { | |
int n = 0; | |
int k = A.length/i; | |
for (int j=0; (j+k)<=A.length; j+=k) { | |
if (a[j+k-1] >= j && a[j+k-1] < j+k) | |
n++; | |
else | |
break; | |
} | |
if (n == i && num < n) | |
num = n; | |
n = 0; | |
for (int j=0; (j+i)<=A.length; j+=i) { | |
if (a[j+i-1] >= j && a[j+i-1] < j+i) | |
n++; | |
else | |
break; | |
} | |
if (n == A.length/i && num < n) | |
num = n; | |
} | |
i++; | |
} | |
return num; | |
} | |
} |
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