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May 5, 2016 20:37
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Michał Wojciechowski's puzzle (blogs.perl.org/users/michal_wojciechowski/2016/05/brutally-solving-a-logic-puzzle-with-perl-6.html)
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$ swipl | |
?- ["puzzle.prolog"]. | |
true. | |
?- S = [_, 3, 17, 5, _, _, 13, _, 7], puzzle(S, O). | |
S = [41, 3, 17, 5, 23, 19, 13, 11, 7], | |
O = [61, 47, 31, 59, 37, 43, 71, 53, 541] ; | |
S = [11, 3, 17, 5, 41, 37, 13, 23, 7], | |
O = [31, 83, 43, 29, 67, 61, 59, 71, 601] ; | |
S = [11, 3, 17, 5, 41, 37, 13, 53, 7], | |
O = [31, 83, 73, 29, 97, 61, 59, 71, 691] ; | |
S = [11, 3, 17, 5, 41, 43, 13, 53, 7], | |
O = [31, 89, 73, 29, 97, 67, 59, 71, 709] ; | |
false. | |
?- |
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:- use_module(library(clpfd)). | |
%% A B C | |
%% D E F | |
%% G H I | |
primes([2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73, | |
79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163, | |
167,173,179,181,191,193,197,199,211,223,227,229,233,239,241,251, | |
257,263,269,271,277,281,283,293,307,311,313,317,331,337,347,349, | |
353,359,367,373,379,383,389,397,401,409,419,421,431,433,439,443, | |
449,457,461,463,467,479,487,491,499,503,509,521,523,541,547,557, | |
563,569,571,577,587,593,599,601,607,613,617,619,631,641,643,647, | |
653,659,661,673,677,683,691,701,709,719,727,733,739,743,751,757, | |
761,769,773,787,797,809,811,821,823,827,829,839,853,857,859,863, | |
877,881,883,887,907,911,919,929,937,941,947,953,967,971,977,983, | |
991,997]). | |
primes_domain(PD) :- | |
primes(P), | |
primes_domain(P, PD). | |
primes_domain([], 2). | |
primes_domain([H|T], H \/ D1) :- | |
primes_domain(T, D1). | |
puzzle(S, [R1, R2, R3, C1, C2, C3, D1, D2, T]) :- | |
S = [A, B, C, D, E, F, G, H, I], | |
[R1, R2, R3, C1, C2, C3, D1, D2 | S] ins 1..100, | |
primes_domain(PD), | |
[R1, R2, R3, C1, C2, C3, D1, D2, T | S] ins PD, | |
all_distinct([R1, R2, R3, C1, C2, C3, D1, D2 | S]), | |
A + B + C #= R1, | |
D + E + F #= R2, | |
G + H + I #= R3, | |
A + D + G #= C1, | |
B + E + H #= C2, | |
C + F + I #= C3, | |
A + E + I #= D1, | |
G + E + C #= D2, | |
R1 + R2 + R3 + C1 + C2 + C3 + D1 + D2 + A + B + C + D + E + F + G + H + I #= T, | |
labeling([], S). | |
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