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Get property name from lambda expression
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using System.Linq.Expressions; | |
/// <summary> | |
/// Returns the name of the specified property of the specified type. | |
/// </summary> | |
/// <typeparam name="T">The type the property is a member of.</typeparam> | |
/// <param name="property">The property expression.</param> | |
/// <returns>The property name.</returns> | |
public static string GetPropertyName<T>(Expression<Func<T, object>> property) | |
{ | |
var lambda = (LambdaExpression)property; | |
MemberExpression memberExpression; | |
if (lambda.Body is UnaryExpression) | |
{ | |
UnaryExpression unaryExpression = (UnaryExpression)(lambda.Body); | |
memberExpression = (MemberExpression)(unaryExpression.Operand); | |
} | |
else | |
{ | |
memberExpression = (MemberExpression)(lambda.Body); | |
} | |
var propertyInfo = memberExpression.Member as PropertyInfo; | |
if (propertyInfo == null) | |
{ | |
throw new ArgumentException("Does not expess a property.", nameof(property)); | |
} | |
return propertyInfo.Name; | |
} | |
// C# 9 version (works for other member types as well) | |
public static string GetMemberName<T>(this Expression<T> expression) => | |
expression.Body switch | |
{ | |
MemberExpression m => m.Member.Name, | |
UnaryExpression { Operand: MemberExpression m } => m.Member.Name, | |
_ => throw new NotImplementedException(expression.GetType().ToString()) | |
}; |
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Awesome, thanks a lot!