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Solving FizzBuzz without if in Elixir
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| fizz_word = fn | |
| (0, 0, _) -> "FizzBuzz" | |
| (0, _, _) -> "Fizz" | |
| (_, 0, _) -> "Buzz" | |
| (_, _, third) -> third | |
| end | |
| fizz_buzz = fn n -> fizz_word.(rem(n, 3), rem(n, 5), n) end |
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