Created
October 16, 2014 15:40
-
-
Save satra/aa3d19a12b74e9ab7941 to your computer and use it in GitHub Desktop.
Distance Correlation in Python
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
from scipy.spatial.distance import pdist, squareform | |
import numpy as np | |
from numbapro import jit, float32 | |
def distcorr(X, Y): | |
""" Compute the distance correlation function | |
>>> a = [1,2,3,4,5] | |
>>> b = np.array([1,2,9,4,4]) | |
>>> distcorr(a, b) | |
0.762676242417 | |
""" | |
X = np.atleast_1d(X) | |
Y = np.atleast_1d(Y) | |
if np.prod(X.shape) == len(X): | |
X = X[:, None] | |
if np.prod(Y.shape) == len(Y): | |
Y = Y[:, None] | |
X = np.atleast_2d(X) | |
Y = np.atleast_2d(Y) | |
n = X.shape[0] | |
if Y.shape[0] != X.shape[0]: | |
raise ValueError('Number of samples must match') | |
a = squareform(pdist(X)) | |
b = squareform(pdist(Y)) | |
A = a - a.mean(axis=0)[None, :] - a.mean(axis=1)[:, None] + a.mean() | |
B = b - b.mean(axis=0)[None, :] - b.mean(axis=1)[:, None] + b.mean() | |
dcov2_xy = (A * B).sum()/float(n * n) | |
dcov2_xx = (A * A).sum()/float(n * n) | |
dcov2_yy = (B * B).sum()/float(n * n) | |
dcor = np.sqrt(dcov2_xy)/np.sqrt(np.sqrt(dcov2_xx) * np.sqrt(dcov2_yy)) | |
return dcor |
yes, this is the same distance correlation.
Small reproducible example:
from sklearn.datasets import load_iris
import pandas as pd
import dcor
# https://dcor.readthedocs.io/en/latest/energycomparison.html
iris = load_iris()
iris_df = pd.DataFrame(data= np.c_[iris['data'], iris['target']],
columns= iris['feature_names'] + ['target'])
print ("dcor distance correlation = {:.3f}".format(dcor.distance_correlation(iris_df['sepal length (cm)'],
iris_df['petal length (cm)'])))
print ("distcorr distance correlation = {:.3f}".format(distcorr(iris_df['sepal length (cm)'], iris_df['petal length (cm)'])))
returns:
dcor distance correlation = 0.859
distcorr distance correlation = 0.859
Can anyone help me how to plot this like a matrix in pandas?
Is it possible to have a distance correlation matrix similar to a correlation matrix?
Thanks a lot.
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
@seanlaw, yes, that seems to be the case.
(Eq. (2.8) - (2.10) in Székely, Rizzo, and Bakirov, 2007)