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@schaunwheeler
Last active March 13, 2023 16:24
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Amortization function
# The MIT License (MIT)
#
# Copyright (c) 2012 Schaun Jacob Wheeler
#
# Permission is hereby granted, free of charge, to any person obtaining a copy
# of this software and associated documentation files (the "Software"), to deal
# in the Software without restriction, including without limitation the rights
# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
# copies of the Software, and to permit persons to whom the Software is
# furnished to do so, subject to the following conditions:
#
# The above copyright notice and this permission notice shall be included in all
# copies or substantial portions of the Software.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
# SOFTWARE.
amortize <- function(p_input = 25000, i_input = .10, n_months = 36,
output = "table", index = NULL) {
n_months <- rep(n_months, length(p_input))
if(is.null(index)) {
index <- matrix(rep(1:length(n_months), each = n_months[1]),
nrow = n_months[1])
} else {
index <- matrix(rep(index, each = n_months[1]), nrow = n_months[1])
}
p_input <- matrix(p_input, ncol = length(p_input))
i_input <- matrix(i_input, ncol = length(i_input))
i_monthly <- i_input / (12)
payment <- p_input * i_monthly / (1 - (1 + i_monthly)^(-n_months[1]))
Pt <- p_input # current principal or amount of loan
currP <- NULL
for(i in 1:n_months[1]) {
H <- Pt * i_monthly # current monthly interest
C <- payment - H # monthly payment minus monthly interest (principal paid for each month)
Q <- Pt - C # new balance of principal of loan
Pt <- Q # loops through until balance goes to zero
currP <- rbind(currP, Pt)
}
amortization <- rbind(p_input, currP[1:(n_months[1]-1),, drop = FALSE])
monthly_principal <- amortization - currP
monthly_interest <- rbind(
(matrix(
rep(payment, n_months[1]),
nrow = n_months[1],
byrow = TRUE) - monthly_principal)[1:(n_months[1]-1),, drop = FALSE],
rep(0, length(n_months)))
monthly_interest[1:nrow(monthly_interest) %% 12 == 0] <-
monthly_principal[1:nrow(monthly_interest) %% 12 == 0] * i_monthly
monthly_payment <- monthly_principal + monthly_interest
installment <- matrix(rep(1 : n_months[1], length(n_months)),
nrow = n_months[1])
input <- list(
"amortization" = amortization,
"payment" = monthly_payment,
"principal" = monthly_principal,
"interest" = monthly_interest,
"installment" = installment,
"index" = index)
out <- switch(output,
"list" = input,
"table" = as.data.frame(
lapply(input, as.vector),
stringsAsFactors = FALSE),
"balance" = as.data.frame(
lapply(input[c("index", "amortization")], as.vector),
stringsAsFactors = FALSE),
"payment" = as.data.frame(
lapply(input[c("index", "payment")], as.vector),
stringsAsFactors = FALSE),
"principal" = as.data.frame(
lapply(input[c("index", "principal")], as.vector),
stringsAsFactors = FALSE),
"interest" = as.data.frame(
lapply(input[c("index", "interest")], as.vector),
stringsAsFactors = FALSE)
)
out
}
@brantmerrell
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Every 12 rows of the result appears to have a different payment number as shown in the screenshot below.

The table in the screenshot was generated using

result <- amortize( p_input=240000, i_input=0.05, n_months=360, output="table", index="test 1" )

image

@schaunwheeler
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Author

Use the function at your own risk. I last looked at this code in 2013. I haven't written anything in R for nearly that long. It could be a bug I never caught, or it could be any number of things that have changed within the R ecosystem between then and now. That's about all I can tell you.

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