If you do not trust seed generators and do not believe your random keyboard smashing is random enough, you can use a dice to generate a random, perfectly distributed IOTA seed.
Just follow the instructions below and write down the seed while you are throwing your dice.
Note that this can be tedious, as between 162 and 243 dice rolls are required to generate the whole seed.
- Roll your dice two times (remember the order of the results).
- If the first roll is a 6, or if the first roll is a 5 and the second roll is 4-6, roll a third time.
- Look up the character in the table below
- Repeat until your seed has 81 characters
| First roll | Second roll | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|
| 1 | A | B | C | D | E | F | |
| 2 | G | H | I | J | K | L | |
| 3 | M | N | O | P | Q | R | |
| 4 | S | T | U | V | W | X | |
| 5 | Third roll 1-2 Third roll 3-4 Third roll 5-6 |
Y | Z | 9 | A B C |
D E F |
G H I |
| 6 | Third roll 1-2 Third roll 3-4 Third roll 5-6 |
J K L |
M N O |
P Q R |
S T U |
V W X |
Y Z 9 |
Guys I need to add a different way of generating an iota seed.
Its easier better simpler and 100% random
You need 9 different colores dice and a bag.
The dice has 6 faces. We only need 3 outcomes per dice. So if 1or2, 3or4, 5or6. 3 possibilities not 6.
3 possibilities times 9 equals 27.
100per cent random.
So 9 dice in a bag. Shake the bag. Pick 1 face of 1 dice in that bag. And you have the car 9 or A-Z