Created
November 16, 2023 23:14
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brackets problem recursive solution with string size reduction
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const tests = [ | |
'()[]{}', | |
'(((]))', | |
'((()))', | |
'](', | |
'(()', | |
'())' | |
] | |
const solutions = [ | |
true, | |
false, | |
true, | |
false, | |
false, | |
false | |
] | |
const isOpening = c => { | |
return ['(', '{', '['].indexOf(c) > -1 | |
} | |
const isClosing = c => { | |
return [')', '}', ']'].indexOf(c) > -1 | |
} | |
const closers = { | |
'(': ')', | |
'{': '}', | |
'[': ']' | |
} | |
const isValid = str => { | |
if (str.split("").some(c => !isOpening(c) && !isClosing(c))) { | |
throw new Error("Chars expected to be from '(', '[', '{', ')', ']', '}'") | |
} | |
if (str.length === 0) { | |
return true | |
} | |
if (!isOpening(str[0])) { | |
return false | |
} | |
let innermostOpenerIndex = 0 | |
while (isOpening(str[innermostOpenerIndex + 1]) ) { | |
innermostOpenerIndex++ | |
} | |
const innermostOpener = str[innermostOpenerIndex] | |
const innermostCloser = str[innermostOpenerIndex + 1] | |
if(closers[innermostOpener] !== innermostCloser) { | |
return false | |
} | |
const stringWithParensRemoved = str.slice(0, innermostOpenerIndex) + str.slice(innermostOpenerIndex + 2) | |
return isValid(stringWithParensRemoved) | |
} | |
tests.forEach((test, i) => { | |
if(isValid(test) !== solutions[i]) { | |
throw new Error(`${test} should be ${solutions[i]}`) | |
} | |
}) |
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