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January 11, 2020 09:19
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Checksum of a proprietary RS485 protocol
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Packets with “?” may have a wrong checksum, I’m not sure about those. | |
Format of a packet seems to be: | |
1 start byte | |
3 bytes header (I don’t understand it yet) | |
1 byte payload length | |
n bytes payload | |
1 byte checksum | |
Interested in what else I found out? Check the project page: | |
https://github.com/scy/votonic | |
My question was: How is the checksum calculated? | |
But @Manawyrm found it out: simple XOR of all the bytes on top of 0x55. | |
Here’s the implementation: | |
https://github.com/scy/votonic/commit/cc3e74565384ab6cd068f9350a35398dcf845240 | |
_ start byte | |
/ _ payload length | |
/ / _ checksum | |
/ / / | |
aa 22 04 f4 03 00 00 00 2e | |
aa 22 08 f4 03 0f 00 00 2d | |
aa 22 0c f4 03 03 00 00 25 | |
aa 22 10 f4 03 02 00 00 38 ? | |
aa 22 10 f4 03 05 00 00 3f | |
aa 22 10 f4 03 07 00 00 3d ? | |
aa 22 10 f4 03 08 00 00 32 ? | |
aa 22 11 f4 03 0b 00 00 30 | |
aa 22 34 f4 03 00 00 00 1e | |
aa 22 38 f4 03 00 00 00 12 | |
aa 22 40 f4 03 00 00 00 6a | |
aa 22 74 f4 03 02 00 00 5c | |
aa 22 c4 f4 03 00 00 00 ee | |
aa 62 f4 04 03 00 c0 00 ae | |
aa 62 f4 08 03 0f 00 03 6e | |
aa 62 f4 0c 03 02 eb ff 70 | |
aa 62 f4 0c 03 03 1e 05 7e | |
aa 62 f4 0c 03 03 21 05 41 | |
aa 62 f4 0c 03 06 50 45 75 | |
aa 62 f4 0c 03 06 50 46 76 | |
aa 62 f4 0c 03 06 50 47 77 | |
aa 62 f4 0c 03 06 50 48 78 | |
aa 62 f4 0c 03 06 50 49 79 | |
aa 62 f4 0c 03 06 50 4a 7a | |
aa 62 f4 0c 03 06 50 4b 7b | |
aa 62 f4 0c 03 06 50 4c 7c | |
aa 62 f4 0c 03 06 50 4d 7d | |
aa 62 f4 10 03 02 00 00 78 ? | |
aa 62 f4 10 03 05 fe ff 7e | |
aa 62 f4 10 03 07 00 00 7d ? | |
aa 62 f4 10 03 08 fe ff 73 ? | |
aa 62 f4 34 03 00 e5 04 bf | |
aa 62 f4 38 03 00 e0 00 b2 | |
aa 62 f4 40 03 00 c0 00 ea | |
aa 62 f4 74 03 02 00 00 1c | |
aa 62 f4 c4 03 00 00 00 ae |
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