Created
June 14, 2020 11:10
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visualise random vs sequential bit allocations
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import random | |
import numpy as np | |
from matplotlib import pyplot as plt | |
fixed_bits = 32 | |
variable_bits = 32 | |
bitlen = fixed_bits + variable_bits | |
iterations = 2048 | |
def longest_match(old, new): | |
old = bin(old)[2:] | |
new = bin(new)[2:] | |
for i in range(0, len(old)): | |
if old[i] != new[i]: | |
return i+1 | |
return -1 | |
def plot(counts, name, subheading): | |
a = np.array(counts) | |
fig = plt.figure(figsize=[7,5]) | |
ax = plt.subplot(111) | |
plt.xticks(np.arange(0, bitlen+1, step=8)) | |
ax.set_xlabel('longest bitmatch') | |
ax.set_ylabel('frequency') | |
ax.set_title(name + ": " + subheading) | |
ax.bar(range(0,len(counts)),counts) | |
plt.savefig(name + ".png") | |
# Set a string of 1s | |
network = (2**bitlen)-1 | |
print("1 ",network,bin(network)) | |
# Squash the variable part to zeroes | |
# Acts like a netmask | |
network = network - ((2 ** variable_bits)-1) | |
print("2 ",network,bin(network)) | |
# count into these bins | |
# use for histogram later | |
histo_counts = [0] * bitlen | |
old_ip = network | |
for i in range(1, iterations): | |
r = random.randrange(0,2**variable_bits) | |
new_ip = network | r | |
n = longest_match(old_ip, new_ip) | |
print(n, hex(old_ip), hex(new_ip)) | |
histo_counts[n-1] += 1 | |
old_ip = new_ip | |
plot(histo_counts, "random", str(fixed_bits) + " fixed + " + str(variable_bits) + " bits variable, " + str(iterations) + " iterations") | |
# reset counts | |
histo_counts = [0] * bitlen | |
old_ip = network | |
for i in range(1, iterations): | |
new_ip = old_ip + 1 | |
n = longest_match(old_ip, new_ip) | |
print(n, hex(old_ip), hex(new_ip)) | |
histo_counts[n-1] += 1 | |
old_ip = new_ip | |
plot(histo_counts, "linear", str(fixed_bits) + "fixed + " + str(variable_bits) + " bits variable, " + str(iterations) + " iterations") | |
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