seanparsons

scala> import scalaz._,Scalaz._
import scalaz._
import Scalaz._

scala> val isOne = (i: Int) => {println("isOne"); if (i == 1) Some(1) else None}
isOne: Int => Option[Int] = <function1>

scala> val isTwo = (i: Int) => {println("isTwo"); if (i == 2) Some(2) else None}
isTwo: Int => Option[Int] = <function1>

seanparsons

object SKI_Applicative {
/*
First, let's talk about the SK combinator calculus and how it contributes to solving your problem.

The SK combinator calculus is made of two functions (aka combinators): S and K. It is sometimes called the SKI combinator calculus, 
however, the I combinator can be derived from S and K. The key observation of SK is that it is a turing-complete system and therefore, 
anything that can be expressed as SK is also turing-complete. Here is a demonstration that Scala's type system is turing-complete 
(and therefore, undecidable) for example[1].

The K combinator is the most trivial of the two. It is sometimes called "const" (as in Haskell). There is also some discussion about 

seanparsons

def validateProduct[T <: Product](product: T): Seq[String] = product.productIterator.flatMap{value => value match {
  case null => Seq("null attributes are not allowed for " + product)
  case string: String if (string.isEmpty) => Seq("Empty strings are not allowed for " + product)
  case innerProduct: Product => validateProduct(innerProduct)
  case _ => Seq()
}}.toSeq