This script will auto-increment your Xcode project's build number for every build (debug & release). It will also increment the third position of a semantic formatted version string only for release builds: Examples: Build number: from 123 to 124 Version string: from 1.2.5 to 1.2.6

run-script.sh

# This script will auto-increment your Xcode project's build number for every build (debug & release).
# It will also increment the third position of a semantic formatted version string only for release builds
#
# Examples:
# Buil number (CFBundleVersion): from 123 to 124
# Version string (CFBundleShortVersionString): from 1.2.5 to 1.2.6
#
# 1. Select your Target in Xcode
# 2. Select "Build Phases" Tab
# 3. Select "Add Build Phase" -> "Add Run Script"
# 4. Paste code below into the "Run Script" section
# 5. Ensure your starting version number (CFBundleShortVersionString) is in semantic versioning format (e.g. 1.0.0)
# 6. Ensure your starting build number (CFBundleVersion) is an integer number (e.g. 1)

#!/bin/bash

# Get project info
buildPlist="${PROJECT_DIR}/${INFOPLIST_FILE}"
buildNumber=$(/usr/libexec/PlistBuddy -c "Print CFBundleVersion" "$buildPlist")
versionString=$(/usr/libexec/PlistBuddy -c "Print CFBundleShortVersionString" "$buildPlist")

# Increment build number for every build
if [ "$CONFIGURATION" == "Debug" ] || [ "$CONFIGURATION" == "Release" ]; then
  # Increment the buildNumber (A.K.A CFBundleVersion)
  buildNumber=$(($buildNumber + 1))
  /usr/libexec/PlistBuddy -c "Set :CFBundleVersion $buildNumber" "$buildPlist"
fi

# Increment version string only for release builds
if [ "$CONFIGURATION" == "Release" ]; then
  #Increment the version string (A.K.A. CFBundleShortVersionString)
  newSubversion=`echo $versionString| awk -F "." '{print $3}'`
  newSubversion=$(($newSubversion + 1))
  newVersionString=`echo $versionString| awk -F "." '{print $1 "." $2 ".'$newSubversion'" }'`
  /usr/libexec/PlistBuddy -c "Set :CFBundleShortVersionString $newVersionString" "$buildPlist"
fi

newSubversion=echo $versionString| awk -F "." '{print $3}'
is "`" simbol legual ?