Count by M (1.5).js

/*
Count by m
Write a function that takes three arguments: n (number), m(number) and direction (string). The function should count to n by intervals of m. If the direction string is "Up", the function should count up to n, if the string is "Down", it should count down. You can assume that both n and m will be greater than 0. Do not print numbers greater than n.
 
Please complete the problem in 2 ways:
1. Using a for loop
2. Using while a loop
 
    count(10, 2, "Up")
    // 2
    // 4
    // 6
    // 8
    // 10

    count(11, 2, "Down")
    // 11
    // 9
    // 7
    // 5
    // 3
    // 1

*/
function count(n, m, direction) {
	if (direction === "Up") {
		for (var i = m; i <= n; i += m) {
			console.log (i);
		} 
	} else {
		for (var i = n; i > 0; i -= m) {
			console.log (i);
		}
	}
}

count(10,2,"Up");
count(11,2,"Down");

Count by M (1.5)_console_dump.txt

Native Browser JavaScript
  
2
4
6
8
10
11
9
7
5
3
1