pig latin and numbers to words excercises

Ruby Basics Lesson

#pig latin
def translate(word)
vowels = ["a", "e", "i", "o", "u"]
 if vowels.include?(word[0])
  return word <<"ay"
  elsif word[0..2] =="sch"
  return word[3..-1] <<word[0..2]<<"ay"
  elsif vowels.include?(word[1]) == false
  return word[2..-1] << word[0..1] <<"ay"
  elsif word[0..1] =="qu"
  return word[2..-1] << word[0..1] <<"ay"
  else
  return word[1..-1] << word[0] << "ay"
end
end 

#numbers to words
class Integer

 def in_words
  numbers = {1 => 'one' , 2=> 'two', 3 => 'three', 4 =>'four', 5=>'five', 6=>'six', 7=>'seven', 8 => 'eight', 9=> 'nine',
 10=>'ten' , 11=> 'eleven', 12=> 'twelve', 13=>'thirteen', 14 =>'fourteen', 15=>'fifteen', 16=>'sixteen', 17=>'seventeen', 
 18 =>'eighteen', 19=>'nineteen'}
 tens = {2 =>'twenty', 3 => 'thirty', 4 => 'forty', 5 => 'fifty', 6 => 'sixty', 7 => 'seventy', 8 =>'eighty', 
 9 =>'ninety'}
  other = { 1000000000000 =>' trillion', 1000000000 =>' billion', 1000000 =>' million',1000 => ' thousand', 100=>' hundred' } 
  ourNum = self
  returnNum = ''

  #goes through other hash and uses recursion
  other.each do |key, value| 
   if ourNum/key >= 1
      nums = (ourNum/key)
      ourNum = ourNum%key
      if ourNum> 0
      returnNum = returnNum + (nums).in_words + value +' '
      else
      returnNum = returnNum + (nums).in_words + value
      end
    end
  end

  #checks tens
  if ourNum/10 > 1
     num = ourNum/10
     ourNum = ourNum%10
      if ourNum>0
       returnNum = returnNum + tens[num]+ ' '
       else returnNum = returnNum + tens[num]
      end
    
  end
  #checks teens and single digits
    if ourNum >= 1
     returnNum = returnNum + numbers[ourNum]  
    end
 #returns the total number in words
   returnNum
end
end