Convert output of django-extensions' `show_urls` to a python list of "simple" URLs

test_views.py

import re

from django.core.management import call_command

from test_plus.test import TestCase


class SmokeTestAllViews(BaseUserTestCase):
    def test_all_view_respones(self):
        """
        Extract all URLs and do a quick sanity check for accessibility.
        Are all responding with 200 or 302 or 404 where expected? Are expected authorizations enforced?

        Clean up the output of django-extensions' `show_urls` command. A bit tricky because it's ANSI-encoded
        for terminal display, so clean that up and filter out the /admin URLs.
        On each remaining line, strip out everything after first tab char.
        """

        # Write output to a file, then read it back in
        tempfile = '/tmp/show_urls.txt'
        with open(tempfile, 'w+') as f:
            call_command('show_urls', stdout=f)
        f.close()
        with open(tempfile) as f:
            content = f.readlines()

        # Strip out the ansi chars
        ansi_escape = re.compile(r'\x1B\[[0-?]*[ -/]*[@-~]')

        url_list = []
        [url_list.append(ansi_escape.sub('', line)) for line in content]  # Strip ANSI chars
        url_list = [line.split('\t')[0] for line in url_list]  # Output is tab-sep; keep data before first tab per line
        url_list = list(filter(lambda x: not x.startswith("/admin"), url_list))  # Filter out all the /admin URLs

        for el in url_list:
            print(el)