Search on Amazon with a Keyword and Get the Result Page

get-amazon-serp.py

import requests
from bs4 import BeautifulSoup

search_keyword = input("Write a keyword to search on Amazon: ")
search_format = search_keyword.strip().replace(' ', '+')

make_url = 'https://www.amazon.com/s?k=' + search_format
print(make_url)

headers = {"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/96.0.4664.93 Safari/537.36", "Referer": "https://www.amazon.com/"}
response = requests.get(make_url, headers=headers)

soup = BeautifulSoup(response.text, 'html.parser')
# Print the nicely formatted source code
print(soup.prettify())

links = soup.findAll('a')
# Print All links in the amazon SERP
for link in links:
    print(link.get('href'))

# Now I need to scrap the first 10 product URLs from this soup. Please help...