Implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial).

WildCard.java

private static String getClean(String pattern){
	StringBuilder sb = new StringBuilder();
	sb.append(pattern.charAt(0));

	for(int i = 1; i < pattern.length(); i++) {
		char ch = pattern.charAt(i);
		if(ch != '*') sb.append(ch);
		else {
			char lastChar = sb.charAt(sb.length()-1);
			if(lastChar!='*') sb.append(ch);
		}
	}

	return sb.toString();
}

// isMatch("x?y*z", "xaybcz") -> true
// isMatch("aa","a") → false
// isMatch("aa","aa") → true
// isMatch("aaa","aa") → false
// isMatch("aa", "*") → true
// isMatch("aa", "a*") → true
// isMatch("ab", "?*") → true
// isMatch("aab", "c*a*b") → false

// dp[i][j] = isMatch considering s.substring(0, i) and p.substring(0, j)

public boolean isMatch(String s, String p) {
	if(p.length() == 1 && p.charAt(0) == '*') return true;
	if(s.length() == 0 && p.length() == 0)
		return true;
	if(s.length() == 0 || p.length() == 0)
		return false;

	p = getClean(p);

	char[] str = s.toCharArray();
	char[] pat = p.toCharArray();
	boolean[][] dp = new boolean[s.length()+1][p.length()+1];

	if(pat[0] == '*')
		dp[0][1] = true;

	dp[0][0] = true;

	for(int i = 1; i < dp.length; i++) {
		for(int j = 1; j < dp[0].length; j++) {
			if(pat[j-1] == str[i-1] || pat[j-1] == '?')
				dp[i][j] = dp[i-1][j-1];
			else if (pat[j-1] == '*')
				dp[i][j] = dp[i][j-1] || dp[i-1][j];
		}
	}

	return dp[s.length()][p.length()];
}

A detailed explanation of wildcard pattern matching and general globbing can be found here:

https://www.partow.net/programming/wildcardmatching/index.html