Created
October 21, 2017 19:30
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Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).
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public List<List<Integer>> zigzagLevelOrder(TreeNode root) { | |
List<List<Integer>> answer = new ArrayList<>(); | |
zigzagLevelOrderHelper(root, answer, 0); | |
return answer; | |
} | |
private void zigzagLevelOrderHelper(TreeNode root, List<List<Integer>> answer, int level) { | |
if(root == null) | |
return; | |
if(answer.size() == level) | |
answer.add(new ArrayList<Integer>()); | |
if(level % 2 == 0) | |
answer.get(level).add(root.val); | |
else | |
answer.get(level).add(0, root.val); | |
zigzagLevelOrderHelper(root.left, answer, level + 1); | |
zigzagLevelOrderHelper(root.right, answer, level + 1); | |
} |
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