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November 17, 2017 16:17
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Rotate an array of n elements to the right or left by k steps.
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// rotate([1, 2, 3, 4, 5], 2, 'r') | |
// [5, 4, | 3, 2, 1] reverse(nums, 0, n-1) | |
// [4, 5, | 3, 2, 1] reverse(nums, 0, k-1) | |
// [4, 5, | 1, 2, 3] reverse(nums, k, n-1) | |
// rotate([1, 2, 3, 4, 5], 2, 'l') | |
// [5, 4, 3, | 2, 1] reverse(nums, 0, n-1) | |
// [3, 4, 5, | 2, 1] reverse(nums, 0, n-k-1) | |
// [3, 4, 5, | 1, 2] reverse(nums, n-k, n-1) | |
public void rotate(int[] nums, int k, char dir) { | |
int n = nums.length; | |
if(n == 0) return; | |
k %= n; | |
reverse(nums, 0, n-1); | |
if(dir == 'r') { | |
reverse(nums, 0, k-1); | |
reverse(nums, k, n-1); | |
} else if(dir == 'l') { | |
reverse(nums, 0, n-k-1); | |
reverse(nums, n-k, n-1); | |
} else throw new IllegalArgumentException(); | |
} | |
public void reverse(int[] a, int i, int j) { | |
while(i < j) | |
swap(a, i++, j--); | |
} | |
public void swap(int[] a, int i, int j) { | |
int temp = a[i]; | |
a[i] = a[j]; | |
a[j] = temp; | |
} |
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