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shettayyy/index.html

Created April 30, 2020 21:44
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Check the performance of the function that sums 'n' numbers using loop and math// source https://jsbin.com/tajiyoq
Raw
index.html
<!DOCTYPE html>
<html>
<head>
<meta name="description" content="Check the performance of the function that sums 'n' numbers using loop and math">
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<script id="jsbin-javascript">
"use strict";
var loopSum = function loopSum(n) {
var sum = 0;
for (var i = 1; i <= n; i++) {
sum += i;
}
return sum;
};
var t1 = performance.now();
var sum1 = loopSum(100000);
var t2 = performance.now();
console.log("t1", t1, "t2", t2, "total sec", (t2 - t1) / 1000, "sum1", sum1);
var mathSum = function mathSum(n) {
return n * (n + 1) / 2;
};
var t3 = performance.now();
var sum2 = mathSum(100000);
var t4 = performance.now();
console.log("t3", t3, "t4", t4, "total sec", (t4 - t3) / 1000, "sum2", sum2);
</script>
<script id="jsbin-source-javascript" type="text/javascript">const loopSum = (n) => {
let sum = 0;
for(let i = 1; i <= n; i++) {
sum += i;
}
return sum;
};
const t1 = performance.now();
const sum1 = loopSum(100000);
const t2 = performance.now();
console.log("t1", t1, "t2", t2, "total sec", (t2 - t1)/1000, "sum1", sum1);
const mathSum = (n) => {
return (n * (n + 1)) / 2;
};
const t3 = performance.now();
const sum2 = mathSum(100000);
const t4 = performance.now();
console.log("t3", t3, "t4", t4, "total sec", (t4 - t3)/1000, "sum2", sum2);</script></body>
</html>
Raw
jsbin.tajiyoq.js
"use strict";
var loopSum = function loopSum(n) {
var sum = 0;
for (var i = 1; i <= n; i++) {
sum += i;
}
return sum;
};
var t1 = performance.now();
var sum1 = loopSum(100000);
var t2 = performance.now();
console.log("t1", t1, "t2", t2, "total sec", (t2 - t1) / 1000, "sum1", sum1);
var mathSum = function mathSum(n) {
return n * (n + 1) / 2;
};
var t3 = performance.now();
var sum2 = mathSum(100000);
var t4 = performance.now();
console.log("t3", t3, "t4", t4, "total sec", (t4 - t3) / 1000, "sum2", sum2);
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