Created
June 30, 2010 07:19
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| def odd(n): | |
| return n%2 | |
| li=[1,2,3,5,9,10,256,-3] | |
| filter(odd,li) //输出[1,3,5,9,-3] |
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Another way is just checking to see if the LSB is set:
That is a much quicker operation than modulus, but not sure if it's faster in a language like python. Cheers!