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June 15, 2019 04:21
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| ''' | |
| Extract a file in a zip file, without opening the zip file | |
| Parameters------- | |
| file_to_get: | |
| filename like 'test.txt' to get | |
| zip_file: | |
| target zip filename like 'zipfile.zip' | |
| zip_dir: | |
| directory path where zip file is. | |
| If zip and python code file are in same directory, '.'. | |
| save_dir = '.' | |
| directory to save exctract file. | |
| If same directory, '.'. | |
| ''' | |
| import glob | |
| import sys | |
| import zipfile | |
| file_to_get = 'test.txt' | |
| zip_file = 'zipfile.zip' | |
| zip_dir = '.' | |
| save_dir = '.' | |
| def extract_file_from_zip(file_to_get, zip_file, zip_dir, save_dir): | |
| zip_path = zip_dir+'/'+zip_file | |
| with zipfile.ZipFile(zip_path, 'r') as myzip: | |
| for n in myzip.namelist(): | |
| if file_to_get in n: | |
| myzip.extract(n, save_dir) | |
| print('extracted:', n) | |
| sys.exit() | |
| print(zip_file, ': not found') | |
| if __name__ == "__main__": | |
| extract_file_from_zip(file_to_get, zip_file, zip_dir, save_dir) |
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