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#!/usr/bin/env python | |
# -*- coding: UTF-8 -*- | |
# http://www.pythonchallenge.com/pc/def/linkedlist.php | |
import urllib, re | |
uri = 'http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=%s' | |
nothing = '12345' # '8022' | |
pattern = 'and the next nothing is (\d+)' |
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kAewtloYgcFQaJNhHVGxXDiQmzjfcpYbzxlWrVcqsmUbCunkfxZWDZjUZMiGqhRRiUvGmYmvnJIHEmbT | |
MUKLECKdCthezSYBpIElRnZugFAxDRtQPpyeCBgBfaRVvvguRXLvkAdLOeCKxsDUvBBCwdpMMWmuELeG | |
ENihrpCLhujoBqPRDPvfzcwadMMMbkmkzCCzoTPfbRlzBqMblmxTxNniNoCufprWXxgHZpldkoLCrHJq | |
vYuyJFCZtqXLhWiYzOXeglkzhVJIWmeUySGuFVmLTCyMshQtvZpPwuIbOHNoBauwvuJYCmqznOBgByPw | |
TDQheAbsaMLjTmAOKmNsLziVMenFxQdATQIjItwtyCHyeMwQTNxbbLXWZnGmDqHhXnLHfEyvzxMhSXzd | |
BEBaxeaPgQPttvqRvxHPEOUtIsttPDeeuGFgmDkKQcEYjuSuiGROGfYpzkQgvcCDBKrcYwHFlvPzDMEk | |
MyuPxvGtgSvWgrybKOnbEGhqHUXHhnyjFwSfTfaiWtAOMBZEScsOSumwPssjCPlLbLsPIGffDLpZzMKz | |
jarrjufhgxdrzywWosrblPRasvRUpZLaUbtDHGZQtvZOvHeVSTBHpitDllUljVvWrwvhpnVzeWVYhMPs | |
kMVcdeHzFZxTWocGvaKhhcnozRSbWsIEhpeNfJaRjLwWCvKfTLhuVsJczIYFPCyrOJxOPkXhVuCqCUgE | |
luwLBCmqPwDvUPuBRrJZhfEXHXSBvljqJVVfEGRUWRSHPeKUJCpMpIsrVMuCmDTZPcAezRnyRTJkYyXk |
iUxaTwANChoKEDAgQAlAAQUOMAA9AAAAAFaYvG1WmLxtADKLBZkAAAJmAAACNKu8
wBMAFzJhMzhhNGE5MzE2YzQ5ZTVhODMzNTE3YzQ1ZDMxMDcwIDg2MTM5ODVldAMA
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NldGb0FBQVRtMXJSR0FnQWhBUndBQAAAAHRRejFqTTRBRnlBUlZkQUNrSUJFU2l3
VU5uMHF1VVVBRElIZ3kyCjVsU1RROFM3R1ZHcU1TeTBxNUlqbjR1cmFJS05zcjRW
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#!/bin/bash | |
# | |
# achieve lowlatency | |
# | |
flow_entries=32768 | |
intf=eth0 | |
core=$(cat /proc/cpuinfo | grep -c processor) | |
rxn=$(ls /sys/class/net/$intf/queues/ | grep rx | wc -l) |
$ sudo lspci -vvv | grep "Ethernet controller"
04:00.0 Ethernet controller: Realtek Semiconductor Co., Ltd. RTL8111/8168/8411 PCI Express Gigabit Ethernet Controller (rev 02)
$
$ sudo lspci -vvv -s 04:00.0
04:00.0 Ethernet controller: Realtek Semiconductor Co., Ltd. RTL8111/8168/8411 PCI Express Gigabit Ethernet Controller (rev 02)
Subsystem: Micro-Star International Co., Ltd. [MSI] Device 519c
Control: I/O+ Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx+
Status: Cap+ 66MHz- UDF- FastB2B- ParErr- DEVSEL=fast >TAbort- <TAbort- <MAbort- >SERR- <PERR- INTx-
Latency: 0, Cache Line Size: 32 bytes
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machine: | |
pre: | |
- | | |
sudo curl -L -o /usr/bin/docker 'http://s3-external-1.amazonaws.com/circle-downloads/docker-1.8.2-circleci' | |
sudo chmod 0755 /usr/bin/docker | |
sudo service docker start | |
dependencies: | |
override: | |
- sudo pip install -U docker-compose==1.4.2 |
1, 有100盏灯,从1~100编上号,开始时所有的灯都是关着的,第一次,把所有编号是1的倍数的灯的开关状态改变一次;第二次,把所有编号是2的倍数的灯的开关状态改变一次;第三次,把所有编号是3的倍数的灯的开关状态改变一次;以此类推,直到把所有编号是100得倍数的灯的开关状态改变一次。问,此时所有开着的灯的编号。
答案:10盏是亮的,分别是1 4 9 16 25 36 49 64 81 100;90盏是灭的。这是因为除了这些平方数以外,其余的任意一个数都能分成不同的两数乘积,质数可以分为1和本身,合数都可以分成若干组乘积(每组两个),因此,这些等都被拉了偶数倍,也就是灭的,平方数因为在被自己的开方数拉是只有一次,所以是奇数次,也就是亮的。随便举两个例子以证明。36分别被1、2、3、4、6、9、12、18、36拉过,共是9次,亮。38分别被1、2、19、38拉过,共是4次,灭。所以10盏是亮的;90盏是灭的
2.假设在一段高速公路上,30分钟之内见到汽车经过的概率是0.95。那么,在10分钟内见到汽车经过的概率是多少?(假设缺省概率固定)
答案:这题的关键在于0.95是见到一辆或多辆汽车的概率,而不是仅见到一辆汽车的概率。在30分钟内,见不到任何车辆的概率为0.05。因此在10分钟内见不到任何车辆的概率是这个值的立方根,而在10分钟内见到一辆车的概率则为1减去此立方根,也就是大约63%。
3.有四个人要在夜里穿过一条悬索桥回到宿营地。可是他们只有一支手电,电池只够再亮17分钟。过桥必须要有手电,否则太危险。桥最多只能承受两个人同时通过的重量。这四个人的过桥速度都不一样:一个需要1分钟,一个需要2分钟,一个需要5分钟,还有一个需要10分钟。他们如何才能在17分钟之内全部过桥?
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#!/usr/bin/env python | |
# -*- coding: UTF-8 -*- | |
# http://www.pythonchallenge.com/pc/def/ocr.html | |
import re | |
# the content of rare_characters.txt is from the | |
# source of ocr.html | |
with open('rare_characters.txt', 'r') as file1: |