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#include <stdio.h> | |
#include <math.h> | |
float a(float x) | |
{ | |
return x + 0.25f - 0.25f; | |
} | |
float b(float x) | |
{ | |
return x - 0.25f + 0.25f; | |
} | |
void show(float x) | |
{ | |
printf("x = %10.10e, a = %10.10e, b = %10.10e\n", x, a(x), b(x)); | |
} | |
int main() | |
{ | |
show(ldexpf(1.0f, 22)); | |
show(ldexpf(-1.0f, 22)); | |
show(ldexpf(1.0f, -26)); | |
show(ldexpf(-1.0f, -26)); | |
/* 他の解については http://blog.practical-scheme.net/shiro/20160513-flonum-question 参照 */ | |
} | |
/* | |
$ ./a.out | |
x = 4.1943040000e+06, a = 4.1943037500e+06, b = 4.1943040000e+06 | |
x = -4.1943040000e+06, a = -4.1943040000e+06, b = -4.1943037500e+06 | |
x = 1.4901161194e-08, a = 0.0000000000e+00, b = 1.4901161194e-08 | |
x = -1.4901161194e-08, a = -1.4901161194e-08, b = 0.0000000000e+00 | |
*/ |
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