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Example of how a Bitcoin block is mined by finding a successful nonce
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import hashlib, struct | |
ver = 2 | |
prev_block = "000000000000000117c80378b8da0e33559b5997f2ad55e2f7d18ec1975b9717" | |
mrkl_root = "871714dcbae6c8193a2bb9b2a69fe1c0440399f38d94b3a0f1b447275a29978a" | |
time_ = 0x53058b35 # 2014-02-20 04:57:25 | |
bits = 0x19015f53 | |
# https://en.bitcoin.it/wiki/Difficulty | |
exp = bits >> 24 | |
mant = bits & 0xffffff | |
target_hexstr = '%064x' % (mant * (1<<(8*(exp - 3)))) | |
target_str = target_hexstr.decode('hex') | |
nonce = 0 | |
while nonce < 0x100000000: | |
header = ( struct.pack("<L", ver) + prev_block.decode('hex')[::-1] + | |
mrkl_root.decode('hex')[::-1] + struct.pack("<LLL", time_, bits, nonce)) | |
hash = hashlib.sha256(hashlib.sha256(header).digest()).digest() | |
print nonce, hash[::-1].encode('hex') | |
if hash[::-1] < target_str: | |
print 'success' | |
break | |
nonce += 1 |
@DarkPhoenix6 look my fork, works well in python 3.6
https://gist.github.com/turunut/7857bd34bac37a04a91a91ee9ea33520
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you wouldn't happen to have a python 3 version of this would you?