Created
January 25, 2020 20:42
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public int reverseBits(int n) { | |
int res = 0; | |
for (int i = 0; i < 32; i++) { | |
int t = n & 1; | |
n = n >> 1; | |
res = res << 1; | |
res = res | t; | |
} | |
return res; | |
// return Integer.reverse(n); | |
} | |
public int reverseBitsWithCache(int n) { | |
byte[] bytes = new byte[4]; | |
Map<Byte, Integer> lookup = new HashMap<>(); | |
int reversedResult = 0; | |
for (int i = 0; i < 4; i++) { | |
bytes[i] = (byte)((n >> (8 * i)) & 0xFF); | |
reversedResult = reversedResult << 8; | |
reversedResult = reversedResult | this.reverseByte(bytes[i], lookup); | |
} | |
return reversedResult; | |
} | |
public int reverseByte(byte a, Map<Byte, Integer> lookup) { | |
// TODO: validate input | |
if (lookup.containsKey(a)) { | |
return lookup.get(a); | |
} | |
int reversedByte = 0; | |
for (int i = 0; i < 8; i++) { | |
int t = (a >> i) & 1; | |
reversedByte = reversedByte << 1; | |
reversedByte = reversedByte | t; | |
} | |
lookup.put(a, reversedByte); | |
return reversedByte; | |
} |
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