Created
October 25, 2013 03:59
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Another implementation of segment tree with lazy propagation with sum of intervals operation
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#include <cstdio> | |
#include <iostream> | |
#include <string.h> | |
using namespace std; | |
#define l(n) 2*n | |
#define r(n) 2*n+1 | |
#define rep(i,a,b) for(i = a;i<=b;i++) | |
#define SIZE 262145 | |
#define MAX 131072 | |
typedef long long ll; | |
long long memo[SIZE]; | |
long long lazy[SIZE]; | |
void update(ll nd,ll s,ll e,ll p,ll q,ll v) | |
{ | |
if(e<p || s>q || s>e) | |
return; | |
if(s >= p && e <= q) | |
{ | |
memo[nd] += (e-s+1) * v; | |
if(s!=e) | |
{ | |
lazy[l(nd)]+=v; | |
lazy[r(nd)]+=v; | |
} | |
return; | |
} | |
update(l(nd),s,(s+e)/2,p,q,v); | |
update(r(nd),(s+e)/2+1,e,p,q,v); | |
memo[nd] += (min(q,e) - max(s,p) + 1) * v; | |
} | |
long long query(ll nd,ll s,ll e,ll p,ll q) | |
{ | |
if(e<p || s>q || e<s) | |
return 0; | |
if(lazy[nd] != 0) | |
{ | |
memo[nd]+=(e-s+1)*lazy[nd]; | |
if(s!=e) | |
{ | |
lazy[l(nd)] += lazy[nd]; | |
lazy[r(nd)] += lazy[nd]; | |
} | |
lazy[nd] = 0; | |
} | |
if(s >= p && e <= q) | |
return memo[nd]; | |
return query(l(nd),s,(s+e)/2,p,q) + query(r(nd),(s+e)/2+1,e,p,q); | |
} | |
int main() | |
{ | |
ll t,n,c,p,q,v,i,cs; | |
cin >> t; | |
while(t--) | |
{ | |
memset(memo,0,sizeof(memo)); | |
memset(lazy,0,sizeof(lazy)); | |
cin >> n >> c; | |
rep(i,1,c) | |
{ | |
cin >> cs >> p >> q; | |
if(cs) | |
cout << query(1,1,MAX,p,q) << "\n"; | |
else | |
{ | |
cin >> v; | |
update(1,1,MAX,p,q,v); | |
} | |
} | |
} | |
return 0; | |
} | |
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