Created
May 28, 2014 03:03
-
-
Save shockalotti/d29021387e8bb3875d28 to your computer and use it in GitHub Desktop.
Go Golang - recursive function, fibonacci sequence
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
package main | |
import "fmt" | |
func fib(n uint) uint { | |
if n == 0 { | |
return 0 | |
} else if n == 1 { | |
return 1 | |
} else { | |
return fib(n-1) + fib(n-2) | |
} | |
} | |
func main() { | |
n := uint(10) | |
fmt.Println(fib(n)) | |
} |
@d4rk5eed it just breaks after 90
�⚡ ./fib2
0 0
10 55
20 6765
30 832040
40 1.02334154e+08
50 1.2586269024e+10
60 1.548008755919e+12
70 1.90392490709134e+14
80 2.3416728348467676e+16
90 2.8800671943708155e+18
100 3.542248481792618e+20
110 4.356677625885483e+22
120 5.358359254990965e+24
130 6.590346215876297e+26
140 8.105590009602348e+28
150 9.969216677189299e+30
160 1.2261325953941875e+33
170 1.5080434001680788e+35
180 1.8547707689471975e+37
190 2.2812172414650363e+39
200 2.8057117299250997e+41
210 3.4507973060837266e+43
220 4.244200115309991e+45
230 5.22002106210068e+47
240 6.420201486372305e+49
250 7.896325826131725e+51
260 9.711838745993384e+53
270 1.194477202498925e+56
280 1.4691098406862176e+58
290 1.8068856563237978e+60
300 2.222322446294202e+62
310 2.733275920376237e+64
320 3.3617071498181414e+66
330 4.134626466684276e+68
340 5.085254383306678e+70
350 6.2544494288205456e+72
360 7.692464272010941e+74
370 9.461105609630573e+76
380 1.1636390653418405e+79
390 1.4311814393143676e+81
400 1.7602368064501377e+83
410 2.1649481537897377e+85
420 2.6627102054807328e+87
430 3.274917057925922e+89
440 4.027881710228336e+91
450 4.95396701187506e+93
460 6.092976636435301e+95
470 7.493865866114232e+97
480 9.216845717656862e+99
490 1.1335970846131328e+102
Profiled using : https://blog.golang.org/profiling-go-programs
import (
"fmt"
)
func main() {
var x = fib(10)
fmt.Println(x)
}
func fib(number int) int {
if number == 0 || number == 1{
return number
}
return fib(number - 2) + fib(number - 1)
}
Linear O(n) implementation as seen in Youtube Video Lecture
3736710778780434371
./fibonacci 0,00s user 0,00s system 48% cpu 0,009 total
package main
func fib(n int) int {
fn := make(map[int]int)
for i := 0; i <= n; i++ {
var f int
if i <= 2 {
f = 1
} else {
f = fn[i-1] + fn[i-2]
}
fn[i] = f
}
return fn[n]
}
func main() {
var x = fib(100)
println(x)
}
Another linear implementation using math/big package for very large integers still blazing fast. try with 20000 or bigger ;)
package main
import (
"fmt"
"math/big"
"os"
"strconv"
)
func fib(n int) *big.Int {
fn := make(map[int]*big.Int)
for i := 0; i <= n; i++ {
var f = big.NewInt(0)
if i <= 2 {
f.SetUint64(1)
} else {
f = f.Add(fn[i-1], fn[i-2])
}
fn[i] = f
}
return fn[n]
}
func main() {
for _, s := range os.Args[1:] {
n, e := strconv.Atoi(s)
if e != nil {
panic(e)
}
fmt.Printf("%s\n", fib(n))
}
}
converted from python science book this method is much faster...
package main
import (
"fmt"
"math/big"
"time"
)
func fib(n int) *big.Int {
fn := make(map[int]*big.Int)
for i := 0; i <= n; i++ {
var f = big.NewInt(0)
if i <= 2 {
f.SetUint64(1)
} else {
f = f.Add(fn[i-1], fn[i-2])
}
fn[i] = f
}
return fn[n]
}
func fib2(n int) *big.Int {
// Initialize two big ints with the first two numbers in the sequence.
a := big.NewInt(0)
b := big.NewInt(1)
// Loop while a is smaller than 1e100.
for i := 0; i <= n; i++ {
a.Add(a, b)
a, b = b, a
}
return a
}
func main() {
start1 := time.Now()
for i := 0; i <= 10000; i++ {
fmt.Printf("Fin(%d) is %d \n", i, fib(i))
}
elapsed1 := time.Since(start1)
start2 := time.Now()
for i := 0; i <= 10000; i++ {
fmt.Printf("Fin(%d) is %d \n", i, fib2(i))
}
elapsed2 := time.Since(start2)
fmt.Printf("time eclibaced1 is %s \n", elapsed1)
fmt.Printf("time eclibaced2 is %s \n", elapsed2)
}
on my PC
time eclibaced1 is 37.3392202s
time eclibaced2 is 4.795402s
package main
func fib(n int) int {
// 0 1 1 2 3 5 8 13 21
f := make([]int, n+1)
f[0] = 0
if n > 0 {
f[1] = 1
for i := 2; i <= n; i++ {
f[i] = f[i-1] + f[i-2]
}
}
return f[n]
}
func main() {
print(fib(100))
}
package main
import "fmt"
func main() {
var num1 int
fmt.Scan(&num1)
fmt.Println(fibonacci(num1))
}
func fibonacci(n int) int {
fib := make([]int, n+1)
fib[0], fib[1] = 0, 1
for i := 2; i <= n; i++ {
fib[i] = fib[i-1] + fib[i-2]
}
return fib[n]
}```
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
try it for fib(100)