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@shohan4556
Created February 11, 2015 19:49
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euler 48 solution
/// Euler problem 48
#include<stdio.h>
#include<math.h>
int long long power(int long long n);
int main()
{
int long long ans,i,j;
ans=0;
for(i=1;i<=1000;i++){
ans= ans+power(i);
ans=ans%10000000000;
}
printf("ans :%lld",ans);
return 0;
}
int long long power(int long long n)
{
int i;
int long long p=1;
for(i=1;i<=n;i++){
p=p*n;
p=p%10000000000;
}
return p;
}
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