Tip to delete tags by pattern

gistfile1.txt

#delete all the remote tags with the pattern your looking for, ie. DEV-
git tag | grep <pattern> | xargs -n 1 -i% git push origin :refs/tags/%
#delete all your local tags
git tag | xargs -n 1 -i% git tag -d %
#fetch the remote tags which still remain
git fetch

Run the following command If you get the message delete doesn't make sense without any refs when trying to delete remote tags:

git push origin --delete $(git ls-remote --tags | grep "tag_prefix.*[^}]$" | cut -f 2)

• git ls-remote --tags will output all remote tags.
• grep "*tag_prefix.*[^}]$" will ignore tags with annotated dereference operator "^{}" since including them errored out.
• cut -f 2 keeps the tag name column only

I accomplished this in posh-git PowerShell on Windows with this if anyone is needing to do the same:
git tag --list 'v[0-9].[1-9].*' --no-column | % { git tag -d $_; git push origin --delete $_ }

Note that I was specifying all builds from v1.1.0 and up, deleting them locally, and from the remote.

Thank you for all these great commands!

Regarding @kerryj89 's version, you can modify it to work with any remote:

git push upstream --delete $(git ls-remote --tags upstream | grep "tag_prefix.*[^}]$" | cut -f 2)

Thanks @kerryj89. This worked fine on macOS! 👏

You can try this. It will delete all matching tag patterns. E.g. for deleting tags starting with v1.0, use git tag -d $(git tag -l "v1.0*")

Delete remote: git push -d $(git tag -l "tag_prefix*") Delete local: git tag -d $(git tag -l "tag_prefix*")

Thank You @chinmaya-kony & @luwes.
Thank You All for the help🙏🏻