Dedupe consecutive sequences from an array

dedupeSequence.js

/*
 This removes consecutive sequences from an array of characters.
 See examples below + a working example @ https://jsfiddle.net/63v4pbq7/5/
*/

dedupeSequence = (seq) => {
  let sequences = [];
  // The longest sequence can be exacly half of the values
  const maxLength = Math.floor(seq.length / 2);
  const stringSequence = seq.join("");
  for (let i = 0; i < maxLength; i++) {
    for (let j = i + 1; j < seq.length - i; j++) {

      // A sequence is a consecutive pattern repeated after the first
      const firstHalf = stringSequence.slice(i, j);
      const secondHalf = stringSequence.slice(j, (j * 2) - i);
      if (firstHalf === secondHalf) {
        sequences.push(firstHalf);
        //console.log("sequence found", firstHalf)
      }
    }
  }

  // We want to remove the longest sequence first, 
  // in order to avoid a small sequence to be removed from a big one
  // i.e BE removed from BEBEBE 
  const sortedSequences = sequences.sort((a, b) => b.length - a.length);
  if (sortedSequences.length) {

    // With this solution, we need to rebuild the sequences - 
    //for each update of the original sequence.
    const [longestSequence] = sortedSequences
    return dedupeSequence(stringSequence.replace(longestSequence, "").split(""));
  } else {
    return seq;
  }
}

// Examples:
const arr = ["A", "B", "E", "B", "E", "B", "E", "B", "E", "D", "E", "D", "E", "B", "E", "D"]
const arr2 = ["A", "B", "E", "B", "E", "B", "E", "B", "E", "D", "E", "D", "B", "E", "D"]

console.log(dedupeSequence(arr)) // ["A", "B", "E","D","E","B","E","D"]
console.log(dedupeSequence(arr2)) // ["A", "B", "E","D"]