Python Read JSON from HTTP Request of URL

gistfile1.py

# Load Json into a Python object

import urllib2
import json
req = urllib2.Request("http://localhost:81/sensors/temperature.json")
opener = urllib2.build_opener()
f = opener.open(req)
json = json.loads(f.read())
print json
print json['unit']

# Array example

import urllib2
import json
req = urllib2.Request("http://vimeo.com/api/v2/video/38356.json")
opener = urllib2.build_opener()
f = opener.open(req)
json = json.loads(f.read())
print json
print json[0]['title']

This is very helpful. Thank you.

Thanks, i use your first example. I think the content will be cached. Any solution for that?

It helps me so much,Thanks

+1 for you sir

So whats the advantage of using .build_opener instead of urlopen?

simple and understandable

I would suggest you don't create a variable named 'json' that overloads the class named 'json' in line 19.

import requests
import json
import urllib

url="http://api.open-notify.org/iss-pass.json"
r=requests.get(url)
t=json.loads(r.content)
for i in range(len(t)):
print(t[i]['state'])

I would suggest using requests

import requests

r = requests.get('URL-HERE')
print r.json()

This is a bit confusing https://gist.github.com/sirleech/2660189#file-gistfile1-py-L19, the variable name is shadowing the library json here. Something like json_response could work better here.