Convenience Function for build Dictionary

fastDictionary.swift

let k = ["a", "b", "c", "d"]
let v = [1, 2, 3, 4]
let p = zip(k, v)

//: build fast dictionary from zipped object
func fastDictionary<K:Hashable, V>(data:Zip2<[K], [V]>) -> Dictionary<K, V> {
    var result:[K:V] = [:]
    for i in data {
        result[i.0] = i.1
    }
    return result
}

//: build fast dictionary from two sequence types.
func fastDictionary<K:Hashable, V>(s1:[K], s2:[V]) -> Dictionary<K, V> {
    return fastDictionary(zip(s1, s2))
}

let d = fastDictionary(k, v)
println(d)