Created
November 20, 2025 05:06
-
-
Save sortira/bdaeca71604dd84d3668e79e75c7a200 to your computer and use it in GitHub Desktop.
stack queue perm
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| #include<stdio.h> | |
| #define MAXSIZE 100 | |
| typedef struct { | |
| int arr[MAXSIZE]; | |
| int top; | |
| } stack; | |
| typedef struct { | |
| int front; | |
| int rear; | |
| int arr[MAXSIZE]; | |
| } queue; | |
| //stack operations | |
| void init_stack(stack* st) { | |
| st->top = -1; | |
| } | |
| int pop(stack* st) { | |
| if(st->top == -1) return -1; | |
| return st->arr[st->top--]; | |
| } | |
| int peek(stack* st) { | |
| if(st->top == -1) return -1; | |
| return st->arr[st->top]; | |
| } | |
| void push(stack* st, int element) { | |
| if(st->top == MAXSIZE - 1) return; | |
| st->arr[++st->top] = element; | |
| } | |
| //queue operations | |
| void init_queue(queue* q) { | |
| q->front = -1; | |
| q->rear = -1; | |
| } | |
| int qempty(queue* q) { | |
| return q->front == q->rear && q->front == -1; | |
| } | |
| void add(queue* q, int element) { | |
| if(q->rear == MAXSIZE - 1) return; | |
| if(q->front == -1 && q->rear == -1) q->front = 0; | |
| q->arr[++q->rear] = element; | |
| } | |
| int qremove(queue* q) { | |
| if(q->front == -1) return -1; | |
| int element = q->arr[q->front]; | |
| q->front++; | |
| if(q->front > q->rear) { | |
| q->front = -1; | |
| q->rear = -1; | |
| } | |
| return element; | |
| } | |
| int qpeek(queue* q) { | |
| if(q->front == -1) return -1; | |
| return q->arr[q->front]; | |
| } | |
| int main() { | |
| printf("Enter the value of n:\n"); | |
| queue p, q, out; | |
| stack s; | |
| init_stack(&s); | |
| init_queue(&p); | |
| init_queue(&q); | |
| init_queue(&out); | |
| int n; | |
| scanf("%d", &n); | |
| printf("Enter the input permutation:\n"); | |
| for(int i = 0; i < n; i++) { | |
| int k; | |
| scanf("%d", &k); | |
| add(&p, k); | |
| } | |
| printf("Enter the output permutation:\n"); | |
| for(int i = 0; i < n; i++) { | |
| int k; | |
| scanf("%d", &k); | |
| add(&out, k); | |
| } | |
| //from this point we cannot call add to queue p anymore only we can call delete operations | |
| while (!qempty(&out)) { | |
| // Case 1: front of P matches front of Out | |
| if (!qempty(&p) && qpeek(&p) == qpeek(&out)) { | |
| add(&q, qremove(&p)); | |
| qremove(&out); | |
| } | |
| // Case 2: top of stack matches front of Out | |
| else if (s.top != -1 && peek(&s) == qpeek(&out)) { | |
| add(&q, pop(&s)); | |
| qremove(&out); | |
| } | |
| // Case 3: need to push from P into stack | |
| else if (!qempty(&p)) { | |
| push(&s, qremove(&p)); | |
| } | |
| // Case 4: no move possible → not a valid permutation | |
| else { | |
| printf("Not possible. Exiting program.\n"); | |
| return -1; | |
| } | |
| } | |
| printf("Final output:\n"); | |
| while(!qempty(&q)) printf("%d ", qremove(&q)); | |
| printf("\n"); | |
| return 0; | |
| } |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment