Created
April 7, 2014 18:33
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My Solution for one company puzzle
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class Node | |
constructor: (@data, @prev, @next) -> | |
@prev.next = this if @prev | |
@next.prev = this if @next | |
class LoopyBuffer | |
_head: null | |
_tail: null | |
_cursor: 0 | |
size: 0 | |
length: 0 | |
constructor: (@size) -> | |
@_readNumberOfLines = 0 | |
processLine: (line) -> | |
if @_readNumberOfLines > 0 | |
@push line | |
@_readNumberOfLines -= 1 | |
else | |
tokens = line.split " " | |
[command, number] = [tokens[0], +tokens[1]] | |
switch command | |
when "A" | |
@_readNumberOfLines = number | |
when "R" | |
@shift number | |
when "L" | |
@list() | |
when "Q" | |
process.exit() | |
return false | |
return true | |
list: -> | |
return unless @tail and @head | |
node = @tail | |
console.log node.data | |
while node isnt @head | |
node = node.next | |
console.log node.data | |
push: (data) -> | |
if not @head and not @tail | |
seed = new Node(data, null, null) | |
@tail = @head = seed.prev = seed.next = seed | |
@length += 1 | |
else | |
if @size is @length | |
# Insert node betwee @tail and @head | |
@tail = @tail.next | |
@head = @head.next | |
@head.data = data | |
else | |
node = new Node(data, @head, @tail) | |
@head = node | |
@length += 1 | |
shift: (number) -> | |
for i in [1..number] | |
return if @length is 0 | |
# Remove @tail node | |
if @tail is @head | |
delete @tail | |
delete @head | |
else | |
prevTail = @tail | |
@tail = prevTail.next | |
@tail.prev = @head | |
@head.next = @tail | |
delete prevTail.prev | |
delete prevTail.next | |
@length -= 1 | |
process.stdin.resume() | |
process.stdin.setEncoding("ascii") | |
buff = null | |
process.stdin.on "data", (chunk) -> | |
lines = chunk.split("\n") | |
unless buff | |
size = +lines[0] | |
process.exit() if size is 0 | |
buff = new LoopyBuffer(size) | |
lines = lines[1..] | |
for line in lines | |
buff.processLine line | |
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