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Getting longest one in array - Kotlin
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| val items = arrayOf( | |
| longArrayOf(200, 0), | |
| longArrayOf(95, 5, 95, 5), | |
| longArrayOf(60, 7, 60, 7, 60, 7), | |
| longArrayOf(43, 7, 43, 7, 43, 7, 43, 7), | |
| longArrayOf(32, 8, 32, 8, 32, 8, 32, 8, 32, 8), | |
| longArrayOf(25, 8, 25, 8, 25, 8, 25, 8, 25, 8, 25, 8), | |
| longArrayOf(20, 9, 20, 9, 20, 9, 20, 9, 20, 9, 20, 9, 20, 9), | |
| longArrayOf(16, 9, 16, 9, 16, 9, 16, 9, 16, 9, 16, 9, 16, 9, 16, 9), | |
| longArrayOf(13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9), | |
| longArrayOf(9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11), // <-- Getting this itme | |
| longArrayOf(9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13, 9, 13), | |
| longArrayOf(9, 16, 9, 16, 9, 16, 9, 16, 9, 16, 9, 16, 9, 16, 9, 16), | |
| longArrayOf(9, 20, 9, 20, 9, 20, 9, 20, 9, 20, 9, 20, 9, 20), | |
| longArrayOf(8, 25, 8, 25, 8, 25, 8, 25, 8, 25, 8, 25), | |
| longArrayOf(8, 32, 8, 32, 8, 32, 8, 32, 8, 32), | |
| longArrayOf(7, 43, 7, 43, 7, 43, 7, 43), | |
| longArrayOf(7, 60, 7, 60, 7, 60), | |
| longArrayOf(5, 90, 5, 90), | |
| longArrayOf(0, 200) | |
| ) | |
| val longestItem = items.sortedBy { it.size }.reversed().first() | |
| // longestItem --> longArrayOf(9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11, 9, 11) | |
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